i need help on a lab
here are the results
Mass of empty beaker and glass rod(62.62)
Mass of beaker, glass rod, hydrated copper sulfate(66.02)
Mass of beaker, glass rod and anhydrous copper sulfate(65.04)
Mass of hydrated copper sulfate(3.4)
Mass of anhydrous copper sulfate(2.42)
Mass of water (0.98)
Determine the percent by mass of water in your sample of hydrated copper(II) sulfate.
my work
0.98/3.4 x 100% = 28.8%
is that right
1 answer
That calculation looks ok to me.
4 answers