3a. V^2 = Vo^2 + 2g*h = 0.
h = -Vo^2/2g + 70 = 422 Ft = Ht. above gnd.
V = Vo + g*Tr = 0.
150 - 32*Tr = 0.
32Tr = 150.
Tr = 4.7 s. = Rise time or time to reach max. ht.
b. h = 0.5g*Tf^2 = 422.
16Tf^2 = 422.
Tf^2 = 26.375.
Tf = 5.14 s. = Fall time.
Tr+Tf = 4.7 + 5.14 = 9.84 s. = Time to reach gnd.
c. Use the given Eq to calculate the ht. at the points shown.
h = 70 + Vo*t + 0.5g*t^2.
(T, h)
(0,70)
(1, 204)
(2. h)
(3, h)
(4, h)
(4.7,422), max ht.
(5,420)
(6, h)
(7, h)
(8, h)
(9, h)
(9.84,0).
I need help making a table
3. One of the fireworks is launched from the top of a 70ft tall building with an initial
upward velocity of 150 ft/sec.
a. What is the equation for this situation? g=-32ft/s^2
b. When will the firework land if it does not explode? 9.28 seconds
c. Make a table for this situation so that it shows the height from time
t = 0 until it hits the ground.
3 answers
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ok it bleeps out the bad stuff. i said what does that mean, and we are so um. we are bad in the head so we use the internet