P1V1/T1=P2V2/T2
I'm not sure you copied all of the problem. I don't know what you're combining. You are making some conversions and some substitutions. Here is some help on what I can determine from your numbers.
P1 is 1.5 atm
V1 is a question mark.
I suppose the question mark means that you are solving for V1 and I assume it is to be determined in liters.
T1 is -20 °C K
What you have written doesn't make sense to me. I assume T1 is -20 C and you want to convert that to Kelvin. To convert to Kelvin, remember Kelvin = 273 + C.
P2 is 2.6 atm
Nothing needs to be done to this since P1 is in atm, also.
V2 is 750 mL with a blank box underneath it.
My best guess is that 750 mL is to be converted to liters. That is done by using the conversion factor of 1 L = 1000 mL.
750 mL x (1 L/1000 mL) = ?? Liters.
T2 is -5 °C K.
Again, I must assume T2 is -5 C and you want to convert to Kelvin. See above conversion for T1.
Plug all those numbers into the formula and solve for V1. The answer will be in liters.
I need help for this question in combining gas law P1V1/T1=P2V2/T2.
P1V1/T1=P2V2/T2
P1 is 1.5 atm
V1 is a question mark.
T1 is -20 °C K
P2 is 2.6 atm
V2 is 750 mL with a blank box underneath it.
T2 is -5 °C K.
How can I combine this question?
1 answer
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