well, consider that 11n just gets bigger and bigger without bound.
csc(x) has an asymptote at x = π
That is, csc(x) -> ∞ as x -> π
So, csc^1(x) -> π as x -> ∞
Or, in the case of our sequence,
lim {csc^(-1) 11n} = π
n->∞
I need help finding the limit of the following sequence or determining that the limit does not exists
{csc^(-1) 11n}
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