Asked by elle
I need help differentiating this question:
3e^-4x
that's three e to the power of negative 4x.
when you differentiate, you get:
-12e^-4x
thanks, but how come it's not -12e^-4x-1, or do i just not minus a one when the power is a co-efficient?
Remember, the differential of e^x is also e^x. So, the final answer is e^xdx. That is, you just differentiate what's in the exponent. In your case, the differential of what's in the exponent is -4, so the final answer is just -4 x the original, or -4 x (3e^-4x).
3e^-4x
that's three e to the power of negative 4x.
when you differentiate, you get:
-12e^-4x
thanks, but how come it's not -12e^-4x-1, or do i just not minus a one when the power is a co-efficient?
Remember, the differential of e^x is also e^x. So, the final answer is e^xdx. That is, you just differentiate what's in the exponent. In your case, the differential of what's in the exponent is -4, so the final answer is just -4 x the original, or -4 x (3e^-4x).
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