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I need 8^(2x-10)=(1/4)^(3x+3) with work shown PLEASE HELP

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8^(2x-10)=(1/4)^(3x+3)
2^(3+2x-10) = 2^(2x-7)
2^(-2+3x+3) = 2^(3x+1)
so
2x-7 = 3x+1
x = -8
Since 8 = 2^3 and 1/4 = 2^-2, we have
8^(2x-10)=(1/4)^(3x+3)
2^(6x-30) = 2^(-6x-6)
6x-30 = -6x-6
12x = 24
x = 2
check: 8^-6 = 1/4^9
2^-18 = 2^-18
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