x-intercept is where y=0, so -3x=36
y-intercept is where x=0, so -4y=36
-3(a+2)-(1-6a)
-3a - 6 - 1 + 6a
3a-7
I missed these problems on my test and I want to see how you would do them the correct way!
1. Find the x and y intercepts: -3x-4y=36
2. Simplify: -3(a+2)-(1-6a)
1 answer