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I"m stuck on this question

"Rays PQ and QR ae perpendicular.Point S lies in the interior of angle PQR.If angle PQS!=4+7a and angle SQR=9+4a,find angle PQS and angle SQR.
PLEASE HELP!!!!

2 answers

4 + 7 a + 9 + 4 a = 90 degrees
13 + 11 a = 90
11 a = 77
a = 7

PQS = 4 + 49
SQR = 9 + 28
Thank you so much!!!!!
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