I know I posted this but you didn't answer! Please help!!!!
Consider the following reaction at 298 K:
C(graphite) +2Cl2 (g) -----> CCl4(l)
Calculate the following quantities.
Delta H: -139 kJ/mol
deltaS(sys)=? J/mol*K
deltaS(surr)=? J/mol*K
deltaS(univ)=? J/mol*K
My answer is:
deltaS(sys)=654.9J/mol*K
deltaS(surr)=0.4664 J/mol*K
deltaS(univ)=655.366J/mol*K
Is this right???????????
chemistry - DrBob222, Wednesday, March 14, 2012 at 11:20pm
Your tables may not be the same as mine but I looked and found
Cl2 for Cl2 = 223.0 J/mol
C(graphite) = 5.740
CCl4(l) = 216.4
If I use S products - S reactants that becomes 216.4 - 5.740 - (2*223.0) and I don't see anything in your answers close to that.
chemistry - Kelsey, Wednesday, March 14, 2012 at 11:41pm
So what are the answers for
deltaS(sys)=? J/mol*K
deltaS(surr)=? J/mol*K
deltaS(univ)=? J/mol*K
I need to verify the correct answers. Could you please tell me...Thanks!
chemistry - Kelsey, Wednesday, March 14, 2012 at 11:44pm
Also I don't know how you are working this problem out.
chemistry - Kelsey, Thursday, March 15, 2012 at 12:34am
DrBob222 could you please answer!!!!!!
8 answers
My answer is:
deltaS(sys)=654900J/mol*K
deltaS(surr)=466.4 J/mol*K
deltaS(univ)=655366J/mol*K
Sorry I forgot to convert to J
also I checked this problem and I only got thedeltaS(surr)=466.4 J/mol*K correct. Please help
216.4 - 5.74 -2(223.0) = ? J/mol = -235.3 J/mol Check that.
dS for surroundings = -dH/T = -(-139,000)/298 = 466.4 J/mol
dS total (universe) = dS sys + dS surr = -235.3J + 466.4 = ? check that.
Check the signs. Check the # s.f.
I am puzzled too. If the dS univ is ok and the dS surroundings is ok, how can the dS system be out of whack since dS univ = dS sys + dS surr