I know I have to take the log of both sides, but I don't seem to get how they work out!

Question

Can anyone explain how to do

3e^(1+x) = 2

AND

10^(2x+3) = 280

If you walk me through one I should be able to figure out the other. Hopefully...

I think you need to go back to one of the log rules:

log[base A](A^n)=n

For example:

log[base10](10^3)=3

similarly

log[base e](e^-x)=-x

Does this help?

Honestly... no X_X. Don't you love college professors who don't /actually/ teach. Thanks for trying. I'm going to try and find someone who can show me.