a^2+b^2=c^2
ada/dt + bdb/dt = cdc/dt
(6)da/dt+12(6) =13(0)
da/dt =−12ft/sec
I haven't done this type of problem in a while, so if someone can just show me how to set it up, I can figure out the rest. (:
"A 13-foot ladder is leaning against a building when its base begins to slide away from the base of the building. By the time the base is 12 feet from the building, the base is moving at the rate of 6 ft/sec. How fast is the top of the ladder sliding down the wall at that point in time?"
1 answer
1 answer