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I have worked this over and over the answer is 37 g. but I am not coming up with that can anyone help?

A flash containing 450 ml of 0.50 M H2SO4 Was knocked onto floor. How many grams of NaHCO3 do you need to put on the spill to neutralize the acid according to the following equation?
H2SO4 (aq) + 2 NaHCO3(aq) to Na3Ag(S2O3)2(aq + NaBr (aq)

1 answer

The equation does not look correct.

H2SO4 (aq) + 2 NaHCO3(s) -> Na2SO4(aq) + 2H2O(l) + 2CO2(g)

the spill contains

450 x 0.50 mmoles of H2SO4 = 225 mmole of H2SO4

we 2 moles of NaHCO3 for each mole of H2SO4 from the equation.

so 2 x 225 mmoles needed = 450 mmoles or 0.450 mole

molar mass of NaHCO3 is 84 g mol^-1

so mass needed =0.450 mol x 84 g mol^-1

= 37.8 g
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