I have worked this over and over still think it's wrong.
find its inverse, domain, and range of f and f^-1
f(x) = 5/ (3x -7)
2 answers
Can someone please help me with this???????
Too bad you didn't show us what your answers are. Maybe they are right, and it would save us the trouble of working it out (again?)
f is a rational function. s such, its domain is all reals except where the denominator is zero. That would be where x = 7/3
The range of f is all reals except 0. There is no number big enough to yield 0 when dividing it into 5.
f^-1(x) = (7x+5)/3x
Domain is all reals except x=0, and range is all reals except y = 7/3. As x gets large, the function approaches 7x/3x = 7/3, but does never equal it. Note that the horizontal asymptote is the same value as the vertical asymptote of f(x).
f is a rational function. s such, its domain is all reals except where the denominator is zero. That would be where x = 7/3
The range of f is all reals except 0. There is no number big enough to yield 0 when dividing it into 5.
f^-1(x) = (7x+5)/3x
Domain is all reals except x=0, and range is all reals except y = 7/3. As x gets large, the function approaches 7x/3x = 7/3, but does never equal it. Note that the horizontal asymptote is the same value as the vertical asymptote of f(x).
0 answers