Asked by patricia
i have two two judges convicting a robberer judge a mean is 33.0 and standard deviation is 2.0. judge b has a mean of 30.0 and a standard deviation of 8.1. which judge would the robber want to sentence?
Answers
Answered by
PsyDAG
I assume the values are the number of years in sentence. Although judge A has a higher mean value, judge B has greater variability. Calculate the Z score for a sentence of 33 from judge B.
Z = (score-mean)/SD = (33-30)/8.1 = ?
Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion higher than that Z score.
Judge A has only .025 probability of giving sentence of 37 years or more (approximately 2 SD above the mean).
What would that probability be for judge B?
Z = (score-mean)/SD = (37-30)/8.1 = ?
Use the same table to make your decision.
Z = (score-mean)/SD = (33-30)/8.1 = ?
Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion higher than that Z score.
Judge A has only .025 probability of giving sentence of 37 years or more (approximately 2 SD above the mean).
What would that probability be for judge B?
Z = (score-mean)/SD = (37-30)/8.1 = ?
Use the same table to make your decision.
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