Could one of you please check when you have time.
Thank you
I have two short questions which I think I know the answer-could you please check?
If I write log(b)x - 2log(b)y as a single logarithm it would be log(b) x/y^2, correct? If not please help
and Is the function f(x) = 1/x a exponential function -I think it would be because it could be a number to the negative power, correct or would that be false
The function f(x) = logx is a logarthmic function-I think this is false because it should be written as log(then a number)x, correct
6 answers
correct, if you meant logb(x/y^2)
F(x)=x^-1 is an inverse function, not an exponential function. Exponential functions are functions which can be written as f(x)=k e^ax
for instance f(x)=3e^-5
or f(x)=12(1-e^(-4x) )
Can it be applied to g(x)=3 a^bx ?
many people include this form in the definition of exponential functions.
I would call f(x)=log x a log function, it is a log whether or not the base is defined. changing bases just changes the slopes of the log curves.
F(x)=x^-1 is an inverse function, not an exponential function. Exponential functions are functions which can be written as f(x)=k e^ax
for instance f(x)=3e^-5
or f(x)=12(1-e^(-4x) )
Can it be applied to g(x)=3 a^bx ?
many people include this form in the definition of exponential functions.
I would call f(x)=log x a log function, it is a log whether or not the base is defined. changing bases just changes the slopes of the log curves.
Thank you for the explanations- I appreciate it
I just noticed something-I had asked about if f(x) = 1/x is an exponential function and I think you rewrote it as f(x) = x^-1. Therefore, f(x) = 1/x is NOT an exponential function, correct?
correct, not an exponential function.
Thank you-could you look at my new post-I just needed clarification about f(x) = logx you said this would be true but doesn't it need parentheses or a separation between log and x for this to be correct?
Thank you
Thank you
2 answers