#2.
Draw the trapezoid. The ends are two triangles with bases x and 21-x (why?)
If the height is h,
x^2+h^2 = 10^2
(20-x)^2 + h^2 = 17^2
equating the two expressions for h^2, we have
17^2 - (21-x)^2 = 10^2 - x^2
Now you can solve for x, and then h.
The area is then (30+9)/2 * h
I have two questions...
#1
if the radius of the two areas is 12in find the length of a chord of an arc of 45, 35, and 60 degrees.
#2 the bases of a trapezoid are 30in and 9in and the nonparallel sides are 10in and 17in. Find the area.
2 answers
Thank you so much Steve!