(1) assuming the gas is ideal, the volume becomes 1/3 of the original.
(2) recall that STP, pressure is at 1 atm. assuming the gas is ideal,
P1*V1 = P2*V2
where
P1 = initial pressure
V1 = initial volume
P2 = final pressure
V2 = final volume
substituting,
1*2000 = (P2)*15
P2 = 2000/15
P2 = 133.33 atm
hope this helps~ :)
i have two questions.
1. generally speaking, if the pressure of a gas is tripled, what will happen to its volume?
2. If I take 2000L of gas at STP and squish it into a gas 15.0L gas cylinder, what will be the pressure inside the cylinder, assuming the temperature is kept constant?
2 answers
thank you very much!
if you could help me with this as well i would be very appreciative!
A steel container holds 750.L of O2 gas at STP.
a) how many moles of O2 does the container hold?
b)how many grams of O2 does the container hold?
c) if the pressure were reduced by removval of gas until it was 380.mm Hg, what mass of gas would remain in the tank?
if you could help me with this as well i would be very appreciative!
A steel container holds 750.L of O2 gas at STP.
a) how many moles of O2 does the container hold?
b)how many grams of O2 does the container hold?
c) if the pressure were reduced by removval of gas until it was 380.mm Hg, what mass of gas would remain in the tank?
2 answers