I have tried to solve this problem in multiple ways, but i keep getting it wrong please help

A 48.0 {\rm kg} ice skater spins about a vertical axis through her body with her arms horizontally outstretched, making 1.50 turns each second. The distance from one hand to the other is 1.5 {\rm m}. Biometric measurements indicate that each hand typically makes up about 1.25 \% of body weight.

What horizontal force must her wrist exert on her hand?

Express the force in part (a) as a multiple of the weight of her hand.

1 answer

centripetal force on the hand is mv^2/r

You have mass m; v is wr or (1.5*2PI/sec)^2 * radius r.