I have tried posting a question on matrix bt i just dont know how to write the question u know the arrangement of numbers.Plz help out.

Answer 1

A =
(a b c)
(x y z)
...
They won't always line up, but it should be decipherable.
The A= has to be on its own line, because it would get in the way of the first row.
If it's an inverse, you might try
(1 2 3)
(4 5 6) ^-1

Answer 2

Thanks let me try

Answer 3

Given that A=(1 5)(3 7) and that B=(7 3)(-4 -2) and that C=AB.Find C-1.Solve for the unknown given that the following is a singular matrix.(1 2)(x x-3)

Answer 4

If (1 2)(x x-3) is singular, then
|1 2|
|x x-3| = 0
so
1(x-2)-2x = x-2-2x = -x-2 = 0
x = -2

C = AB =
(-13 -7)
(-7 -5)
So, C^-1 =
(-5/16 7/16)
(7/16 -13/16)

Or, you can find A^-1 and B^-1
and then C^-1 = (AB)^-1 = B^-1A^-1

Answer 5

oops
x-3-2x = 0
x = -3

Answer 6

x-3x-2x i hav gotten till there but am trying to get how u got x=-3

Answer 7

huh? This is Algebra I
x-3-2x = 0
-x-3 = 0
x = -3