I have to use my answer from a previous question (factorise and solve x^2+x-30=0 which i factorised as (x-5)(x+6)=0 and then solved as x=5 or x=-6) i now have to explain how i can use this answer to solve th equation 4x^2+4x-120=0 and then say what are the solutions?
Please could you help me!!!!!
Thank you
2 answers
Do you see a numeric factor that is common in each term? Factor that number from each term. What is left?
Substitute each value in the second equation to see what fits.