I have to calculate the concentration of I2 produced (# of moles of I2 produced / L) based on the stoichiometric ratio in the following equation.

Question

2S2O3^2- + I2 -> 2I^- + S4O6^2-

Would the # produced be 2 for I2. I am not sure what to use for L?

Answer 1

If you know the number of moles of S2O3^2- then the number of mols I2 will be 1/2 that. I suspect you have M and L of S2O3^- and M x L = moles S2O3^2-.

Answer 2

All I have is the concentration of S2O3^-2 which is 3.33e^-3M. How would I find moles? For the experiment we used 2.50mL of Na2S2O3. Do I use this to find moles?

Answer 3

moles = M x L

Answer 4

Would it be over the total liter of solution from the flask?