I have this question and I am pretty sure on what to use to solve it but I am just stuck. The reaction of 8 g of hydrogen and 28 g of carbon monoxide gave 16 g of methanol. What was the theoretical yield if the percent yield was 50%?

Question

I have this question and I am pretty sure on what to use to solve it but I am just stuck.  The reaction of 8 g of hydrogen and 28 g of carbon monoxide gave 16 g of methanol. What was the theoretical yield if the percent yield was 50%?

actual yield
________________ X 100% = percent yield
theoretical yield

Any help or explantion of the process would be greatly appreciated.

DrBob222 · Answer

(Actual/theoretical)*100 = 50 (A/T) = 50/100 = 0.50 A = 0.5T or T = A/0.5 = 2A Theo = 2*16(from the problem) = 32 g.