Volumebase*molaritybase=volumeacid*molarityacid
Volume acid= 71.7ml*.182M/.2086M
I have this question:
A 71.7-mL solution of 0.182 M NaOH is titrated with 0.2086 M HC.
And I got the rest of the question of right...but for this one part.
4.) after addition of 50.0 mL of HCl
i keep on getting 12.95 but I'm wrong...can someone tell me what to do?
3 answers
...and what do I do withe 50?
*with the