review the point-slope form. You will easily see that the equation is
y-2 = 5(x+2)
I have the following question on a warm-up :
What is the equation of the line that passes through the point {-2, 2} and has a slope of 5?
Can someone help me to figure out the answer.
4 answers
wouldn't it be y + 2 = 5(x+2) ?
nvm, I understand now
THANKS FOR THE HELP :)
THANKS FOR THE HELP :)
(-2, 2), (x, y)
m = (y-2)/(x+2) = 5,
y-2 = 5x + 10,
Y = 5x + 12.
Or:
Y = mx + b.
2 = 5*(-2) + b.
b = 12.
Y = 5x + 12.
m = (y-2)/(x+2) = 5,
y-2 = 5x + 10,
Y = 5x + 12.
Or:
Y = mx + b.
2 = 5*(-2) + b.
b = 12.
Y = 5x + 12.