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I have the following question on a warm-up :

What is the equation of the line that passes through the point {-2, 2} and has a slope of 5?

Can someone help me to figure out the answer.

4 answers

review the point-slope form. You will easily see that the equation is

y-2 = 5(x+2)
wouldn't it be y + 2 = 5(x+2) ?
nvm, I understand now
THANKS FOR THE HELP :)
(-2, 2), (x, y)
m = (y-2)/(x+2) = 5,
y-2 = 5x + 10,
Y = 5x + 12.

Or:
Y = mx + b.
2 = 5*(-2) + b.
b = 12.
Y = 5x + 12.
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