front hemisphere volume is 2/3 pi * 3^3
middle cylinder volume is pi * 3^2 * 12
tail cylinder is pi * 3^2 * 4
Add 'em up. I get 508.93
Maybe I misunderstood the problem.
Anyway, having the volume of the model, the real sub is scaled up by a factor of 20*12 = 240
So, the volume is scaled up by a factor of 240^3
I have the answer to the first part of the question, which is What is the volume of Ted's Submarine model. The answer is 490.08=volume. The second part of the question is if 1 inch in the model represents 20 feet in the actual submarine, what is the volume of the actual submarine. The front round part is 3 inch radiusl the middle part is radius 3 inch/length 12 inches; the tail is 3 inch radius/length is 4 inches. Having a problem figuring this part out.
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