#1,10 and 12 are correct, you probably meant to type "x varies inversely as y^2.." in #12
for #4 all you have to do is say
y = k/x , sub in the x and y values given
so
2=k/6
k = 12
then the equation you are asked for would be
y = 12/x
I have some questions that I don't understand and need to be checked please?
Slove the problem.
1. y varies directly as z and y=187 when z=17. Find y when z=15
-This is how I did it: 187=k*17, I divided by 17 on both sides and got k=11, then I plugged it back into the equation for k and got 165.
If y varies inversely as x, find the inverse variation equation for the situation.
4.y=2 when x=6 (I don't understand this question)
Solve the problem.
10. x varies inversely as v, and x=8 when v=4. Find x when v=16
-This is what I got: 8=k/4, I multiplied each side by 4, I got k= 32, I plugged it back into the equation, x=32/16, x=2
12. y varies inversely as y^2, and x=3 when y=8. Find x when y=2
This is what I got: 3=k/(8^2), 3=k/64, I multiplied each side by 64, I got k=192, I plugged back into the equation, x=192/(2^2), x=48
2 answers
If A varies directly as B, and A =7 when B =2. Find B when A =21