Asked by robin
I have right triangles I need to solve. Can you see if I am doing them correctly or screwed up..1) Rt < is in left corner C: Opposite is 60 deg< A, last angle is at top- 30 deg <. line segment of AB is 10. Hypo is f. I got 10 0r 12.5 for answer. 2) Triangle is ABC with rt angle on left. AB is 10. hyp is 20, altitude is H. I got 3 sq rt of 10 for answer. 3) rt triangle with left side 90 deg <. Hypo is b, altitude is 4, base AC is a. I got a=6, b=4. Did I bomb?
Answers
Answered by
Steve
1)
in a 30-60-90 triangle, the sides are in the proportion 1:√3:2
2)
h^2+10^2 = 20^2
3)
a^2+4^2 = b^2
unless you know one of the other angles, there are lots of a and b which will work.
in a 30-60-90 triangle, the sides are in the proportion 1:√3:2
2)
h^2+10^2 = 20^2
3)
a^2+4^2 = b^2
unless you know one of the other angles, there are lots of a and b which will work.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.