The angle is limited by the required Mechanical Advantage(M.A):
M.A. = 1.21*10^4N / 3.3*10^2N = 0.3666*10^2 = 36.7=The required M.A.
M.A. = 1/sinA,
36.7 = 1/sinA,
Cross multiply:
36.7sinA = 1,
sinA = 1/36.7 = 0.0272,
A = 1.56 Deg, max.
I have one problem I just can't figure out, A machine in an ice factory is capable of exerting 3.30 * 10^2 N of force to pull large blocks of ice up a slope. The blocks each weight 1.21 * 10^4th N.
Assuming there is no friction, what is the max angle that the slope can make with the horizontal if the machine is able to pull the blocks up the slope. in degrees.
1 answer
1 answer