well, first of all that is a parabola as you know.
If you invert it, it is likely to have two values of the ordinate for every value of the abscissa. In other words the inverse will not likely really be a function.
However to do what you want to do, use x for y and y for x and then solve for y.
x = -3y^2 - 18 y - 25
3 y^2 + 18 x + 25 = -x
y^2 + 6 y + 25/3 = -x/3
y^2 + 6 y = -x/3 -25/3
y^2 + 6 y + 9 = -x/3 -25/3 + 27/3
(y+3)^2 = -x/3 + 2/3
right there you can see that for a single value of x you get two values of y, one + and one - because the squares are the same.
y+3= + or - sqrt (2/3 - x/3)
I have no idea how to do inverse functions...
How would I do this question?
Y=-3x^2 - 18x - 25
2 answers
Oh and also it is imaginary for (2-x) negative or x > 2
In other words the new inverse curve is open to the left with a vertex at (2,-3)
In other words the new inverse curve is open to the left with a vertex at (2,-3)