I have matrix A = -1 0

Question

0 -1

B = 0
1

c = 1
0

find n that A^n * matrix B = C

find A^2014

Answer 1

If you take (-1) out of matrix A as a scalar, you'll notice that A is actually (-1)*I, where I is the identity matrix.

Hence, A^n will be the identity matrix if 'n' is even, and it will be A if 'n' is odd.

A^2014 = I

It's not clear what matrices B and C are in your question, but I think you'll be able to solve it with this information.