Asked by bob
I have found a balanced redox equation for removal of silver sulfide using sodium hydrogen carbonate in aluminium to say:
2Al + 3Ag2S + 6H2O --> 6Ag + 2Al2(OH)3 + 3H2S
What happens to the Na and C component of the sodium hydrogen carbonate? And why is it not included on LHS of equation?
2Al + 3Ag2S + 6H2O --> 6Ag + 2Al2(OH)3 + 3H2S
What happens to the Na and C component of the sodium hydrogen carbonate? And why is it not included on LHS of equation?
Answers
Answered by
DrBob222
The Al and Ag2S (with water) is an electrolytic cell but it needs something ionic to conduct the electrons between the Ag^+ of Ag2S and Al metal. NaHCO3 does that job. In fact, ANYTHING ionic will work. But the ionic compound doesn't enter into the reaction, other than the conducting of electrons from one electrode to the other, and it isn't included in the redox equation.
Answered by
bob
Thank you!!
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