calculate the charge of 1.56E20 electrons, you know the charge on each electron.
then calculate time, knowing q
.05t=ln (q/2)
I have been working on my Phys homework and came accross this question that is giving me some trouble:
The charge (coul) on an object increases according to (q) = (2 coul)e[(0.050/sec)(t)], where t is in seconds. At how many seconds is the object deficient 1.56 x 10^20 electrons (from neutral)?
0
12.56
21.94
28.0
41.21
50.5
65.9
105
874
1000
1 answer
1 answer