The centripetal acceleration is V^2/R = 2.0 m/s^2, and the centripetal force is
(M)(V^2/R)
where M is the combined mass of bike and child.
i have been asking physics questions on this and some people give me the formula, i'm getting the correct answers..please can the same people help me on this that helped me before..
A child rides a bicycle in a circular path with a radius of 2.0 m. The tangential speed of the bicycle is 2.0 m/s. The combines mass of the bicycle and the child is 43 kg. What is the magnitude of the bicycle's centripetal acceleration?
What is the magnitude of the centripetal force on the bicycle?
3 answers
so 2.0 m/s^2
86N
86N
Yes. That's about 20 lb. The bike rider will have to lean toward the center of the circle to keep from tipping over.
2 answers