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A 0.1 mol L-1 water solution of NH4CH3CO2 has a pH of approx 7. Explain this using two equations.

I have one equation
CH3COO-(aq) + H2O(l) --> CH3COOH(aq) + OH-(aq)

What could the other equation be?

NH4CH3CO2 is the salt of a weak acid and a weak base.

The equation is OK for a weak acid, you need a similar one for a weak base.

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