I have a reaction here:
2Na3PO4.12H2O + 3BaCl.2H2O --> Ba3(PO4)2 + 6NaCl + 30H2O
and a question:
0.349g of BaCl2.2H2O and 0.624g of Na3PO4.12H2O are dissolved in 500mL of water to form a solution - how many grams of the excess reactant remain after the reaction has gone to completion?
I know that the reactant in excess is the sodium phosphate, and that the answer is 0.362g, but I can't figure out how to get there. Also, is the reaction wrong because the question says BaCl2 and the reaction I made has BaCl, but that's how it worked, so I'm just confused!
1 answer
Actually, sorry, the amount LEFT OVER is .262g of Na3PO4 - .362 was the amount used.
2 answers