Asked by Nancy
I have a problem like this:
CHCl3 + Cl2 = CCl4 +HCL
This is the rate table:
CHCL3 Cl2 Initial Rate
.010 .010 .0035
.020 .010 .0069
.020 .020 .0098
.040 .040 .027
They want me to find the rate constant and the rate law.
CHCl3 + Cl2 = CCl4 +HCL
This is the rate table:
CHCL3 Cl2 Initial Rate
.010 .010 .0035
.020 .010 .0069
.020 .020 .0098
.040 .040 .027
They want me to find the rate constant and the rate law.
Answers
Answered by
Nancy
However, when I try to find the rate constant I get 3.5. My book says 3.5^-.5. I don't know how they got this.
.0069= (.010)^.5(.020)=approx 3.5
but the book says 3.5M^-1/2*s-1
Also I am wondering if there are three reactants in a problem, is there any difference how it is done?
.0069= (.010)^.5(.020)=approx 3.5
but the book says 3.5M^-1/2*s-1
Also I am wondering if there are three reactants in a problem, is there any difference how it is done?
Answered by
DrBob222
If you will calculate k for ALL trials, all come out to about 3.5 and from your data 3.5 surely is correct. The only suggestion I have is that sometimes they place an exponent at the top of the table so that all of the rates would be x 10^-5 or something like that.
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