I have a problem.....

-4(2x-3)=-8x+5

I understand first you distribute the -4 so you would have

-8x+12=-8x+5

Then if you try and move x over to either side you completley get rid of x.... am I missing something or is this problem not solvable?

Thank you

I think I just solved my own question :)

there is no solution....I just remember that is a possibility.

I was stuck in the mindset that there is always a solution, but I could not find it lol

Actually, there is a solution.

-8x+12= 8x + 5
subtract 8x from both sides...
-8x-8x+12=5
now subtract 12 from both sides...