mass metal x specific heat metal x (Tfinal-Tinitial) + mass water x specific heat water x (Tfinal-Tinitial) = 0
The above will solve any of these problems. Just plug in the numbers and solve for the one unknown.
I have a few problems im having trouble with, any help..?
1.
If a peice of aluminum with mass 3.90g and a temperature of 99.3C is dropped into 10.0cm^3 of water at 22.6C, what will be the final temperature of the system?
2.
If a peice of cadmium with a mass 65.6g and a temp. of 100.0C is dropped into 25.0 cm^3 of water at 23.0C, what will be the final temp.
3.a piece of unknown metal with mass 23.8g is heated to 100.0C and dropped into 50.0cm^3 of water at 24.0.The final temp is 32.5C. What is the specific heat.
Help, these are soo confusing!!
4 answers
how do i know the specific heat?
I'm surprised they aren't given in the problem. At any rate, look up the specific heat of Al from problem 1 and Cd from problem 2. Problem 3 gives you temperatures and you are to calculate specific heat. The specific heat of water is 4.184 Joules/grams or 1.0 calories/gram.
Number one is about 28.5 C
2 answers