1.
The aluminum coefficient is 26x10^-6 and the iron rod coefficient is 12x10^-6.
deltaL=L*coeff*(Tf-Ti)
aluminum
Liron-.0019=L*cal*(4-64)
iron:
Liron=L*cfe(4-64)
substuting from the second into the first.
L*cfe(-60)-.0019=L*cal*(-60)
you take if from here, solve for L
3. find the moles of added gas, then using ideal gas law, change moles by adding.
I have a few physics questions that I don't understand. Two are thermal expansion problems and the other is an ideal gas law problem.
1. Two rods, one made of iron and the other of aluminum, have the same initial length at 64.00 deg. C? When the temperature drops to 4.00 deg. C the aluminum rod is 1.900 mm shorter than the iron rod. What was the initial length of the rods?
The aluminum coefficient is 26x10^-6 and the iron rod coefficient is 12x10^-6.
2. A plate made of steel has a 18.9979 mm diameter hole cut into it. A 19.0000 mm diameter ball made of glass is sitting in the hole. Both are at an initial temperature of 9.00 deg. C. If the plate and ball are both heated, at what temperature will the ball just fit through the hole?
(Steel coefficient = 12x10^-6 and glass coefficient = 9x10^-6).
For the next problem, I got the first part but I can't get part B.
3. A. What is the gauge pressure in a 29.0 deg. C car tire with a volume of 39.00 litres and containing 2.20 moles of gas?
For my answer I got: 4.03x10^4 Pa
3B. If 4.00 litres of gas initially at 1.00 atm pressure and 29.0 deg. C is added to tire, what will the gauge pressure be?
How should I manipulate the equations for these problems? Thank you!!
1 answer
1 answer