AD/sin75° = 100/sin65°
AD = 106.58
CD^2 = 50^2 + 106.58^2 - 2*50*106.58 cos50°
CD = 83.72
Hmmm. we're close. Better check
(a) my math
(b) your math
On part b, ya got me. what are α and β supposed to be? Maybe they are to be substituted for the actual angles we used to compute the distances. Then the formula can be used for other angle values.
I have a diagram of how far a discus was thrown.
From A to B is 100m, C is perpendicular to A, from A to C is 50m, A and B are connected to D (it should be a triangle), A has a 40° angle and B has a 75° angle. C is not perpendicular to D btw..
a. Find AD and use it to find CD.
*AD=107.33m, CD=84.38m is that correct?*
b. Find an expression for the distance from Point A to point D, in terms of α and β. Then use that to find and expression for CD, in terms of α and β.
Huh?? I'm confused, help me please!
3 answers
I double checked my math, and you're right.
For part b, they gave the same diagram except for angle A it's α instead of 40° and angle B is β.
For part b, they gave the same diagram except for angle A it's α instead of 40° and angle B is β.
Steve!!! Your grounded! I'm so glad I found this website you little piece of crap.