3g CaCl2/0.5 L = 6/L = 0.6g/dL
dilute 10 mL to 1000 mL; new concn is
0.6g/dL x (10/1000) = 6E-3g/dL
mols = 6E-3/111 = approx 5.41E-5 mols in 6E-3g CaCl2.
Then 5.41E-5 mol/dL = 5.41E-4 mol/L - 5.41M.
I've estimated here and there; you should go through the math yourself including the molar mass of CaCl2.
I have 3 grams of CaCI2 and dissolve this into 0.5 L water. What is the concentration in g/dl (grams/deciliter)? I take 10 milliliters of this solution and add it to 990 milliliters of watet fo a total of 1000 milliliters. What is the concentration of this new dilution in terms of molarity? I Must convert the mass concentration to moles/L, then convert to dl terms to liters, then use the dilution formula.the final unoys should be in moles/liter
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Thank you :)