y = (√x - 2)/(√x + 2)
by the quotient rule
dy/dx = [ (x^(1/2) + 2)( (1/2)x^(-1/2) - (x^(1/2)- 2)((1/2)x^(-1/2) ] / (√x+2)^2
= (1/2)x^(-1/2) [ x^(1/2 + 2 - x^(1/2) + 2]/(√x+2)^2
= (1/2)(1/√x)(4)/(√x+2)^2
= 2/(√x(√x+2)^2 )
I hate these
Y= (Square root of x) - 2
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(square root of x) + 2
Calculate dy/dx
Please help, thank you
1 answer