I had to solve (100-4x)/3=(5x+6)/(4)+6. I converted the fractions into twelfths, but from there I didn't know how to isolate the x's. How can you get them on there on side when they're partr of a fraction? Would you please be able to show me step by step how to do this? Thanks, Jaymie.

Question

I had to solve (100-4x)/3=(5x+6)/(4)+6.  I converted the fractions into twelfths, but from there I didn't know how to isolate the x's.  How can you get them on there on side when they're partr of a fraction? Would you please be able to show me step by step how to do this? Thanks, Jaymie.

MathMate · Answer

(100-4x)/3=(5x+6)/(4)+6
You have done the first step, found the LCM and convert them all over 12.
4(100-4x) 3(5x+6) + 72
---------= ------------
12 12
Now multiply both sides by 12 to remove the common denominator:
4(100-4x)=3(5x+6) + 72
The next step would be to expand and remove the parentheses using the distributivity properties of multiplication. I am sure you can handle the rest.
Post if you get stuck.