I guess I'm missing something here...but I've approached this question in every possible angle and im just not getting it! Could somebody point me in the right direction? Here is the question:
If the measured net radiation (Q*) for the lawn of your home in August is 700 W/m^2 and a typical Bowen ratio is 0.5, how much of this energy is being transferred to the atmosphere as heat and how much is being transferred in the form of evaporating water? Assume energy that is going into the ground is negligible Q(G) = 0.
Surface energy balance is: Q* = Q(H) + Q(E) + Q(G)
Bowen ratio = Q(H)/Q(E)