i got the wrong answer. the correct answer is ln(2).

Question

here is problem:
∫cosx/(1+sinx) dx from 0 to pi/2

Answer 1

∫cos(x)/(1+sin(x)) dx =

∫d[sin(x)]/(1+sin(x))=

Ln[1 + sin(x)]

So, the integral from zero to pi/2 is
Ln(2) - Ln(1) = Ln(2)

Answer 2

thanks