Question

I get confused when solving for some of the fractions in my problem. how would you solve for 1+(-2/(sqroot 5))? I just need a refresher on the order of operations for it. Thanks!

Answer 1

when you have a term squareroot (for example sqrt(x))in the denominator, multiply it with itself such that the multiplier is equal to one ( sqrt(x)/sqrt(x) ) to remove the squareroot,, in this problem:
1+(-2/(sqroot 5))
1+(-2/(sqroot 5))*(sqrt(5)/sqrt(5))
1+{[-2*sqrt(5)]/5}
therefore:
{[5-2*sqrt(5)]/5}

so there,, :)