I don't want the answer I want to be taught how to solve it. Okay so the question is diameter=25in. A=(3.14)(12)^2 Then there is a circle with a line through it and it says 14yd. Okay so I am assuming I solve the area first A=(3.14)(12)^2=452.16 But after that
2 answers
I don't know what to do.
If the 2nd circle's line is a diameter of 14, then its area is done the same way: pi*7^2 = 49pi
By the way, if the diameter is 25, the radius is 12.5, not 12.
Unless you can tell more about the line and its relation to the 2nd circle, I can't figure out what it is you want to know.
Now, if the 14yd line is a chord in the circle of diameter 25, then maybe you want to know how far from the center the chord lies, say a distance x.
If you draw a radius perpendicular to the chord, then you will have two right triangles, with legs x and 7, and hypotenuse 12.5
Then x^2 +7^2 = 12.5^2
By the way, if the diameter is 25, the radius is 12.5, not 12.
Unless you can tell more about the line and its relation to the 2nd circle, I can't figure out what it is you want to know.
Now, if the 14yd line is a chord in the circle of diameter 25, then maybe you want to know how far from the center the chord lies, say a distance x.
If you draw a radius perpendicular to the chord, then you will have two right triangles, with legs x and 7, and hypotenuse 12.5
Then x^2 +7^2 = 12.5^2
3 answers