I don't want someone to do this for me-I'm just totally lost and don't even know where to start-I'm totally lost on this one- the earth is surrounded by an electric field with a strenth of 100 N/C at the surface. Its electric properties are the same as a point charge located at its center. How would the gravatational force and electrical force compare foor an electron at earth's surface. Compare magnitude and direction.

Question

I don't know where to even start-this is a high school Physics, not AP, and I have the formulas but I don't know where I find the point charge etc to work with-Any help-thank you

Answer 1

Relax. This is pretty easy. Not even AP

The electrical force on an electron at the Earth's surface is
F_e = E*e ,
where
e is the electron charge and E is the field strength they gave you.

The gravitational force on an electron at the same place is
F_g = m_e*g
where m_e is the mass of the electron and g is the acceleration of gravity.

You should know where to look up e, m_e and g.

Compute and compare the two forces.

Answer 2

Now that doesn't look so hard-
Thanks for breaking it into smaller steps for me