Asked by hipniblet
i dont understand this question:(
Study Figure 10-3. How much nitrogen-14 will be produced from a 200-g sample of carbon-14 after 17,190 years?
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Study Figure 10-3. How much nitrogen-14 will be produced from a 200-g sample of carbon-14 after 17,190 years?
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Answers
Answered by
DrBob222
Solve for k as in the earlier problems.
I think figure 10-3 just gives you the disintegration process. it is a beta emitter so 6C^14 ==> -1e^o + 7N14
Apply ln (No/N) = kt
You know No is 200 g C-14
You want to solve for N
You know k
You know t is 17,190 years
N will tell you how much C-14 is left at the end of 17,190 years.
200 g C-14 initially - C-14 left = grams C-14 that was converted to N.
The only thing left is to convert the mass of C to mass N,
mass C-14 converted to N14 x (atomic mass N-14/atomic mass C-14) = ? g N-14. Post your work if you get stuck.
I think figure 10-3 just gives you the disintegration process. it is a beta emitter so 6C^14 ==> -1e^o + 7N14
Apply ln (No/N) = kt
You know No is 200 g C-14
You want to solve for N
You know k
You know t is 17,190 years
N will tell you how much C-14 is left at the end of 17,190 years.
200 g C-14 initially - C-14 left = grams C-14 that was converted to N.
The only thing left is to convert the mass of C to mass N,
mass C-14 converted to N14 x (atomic mass N-14/atomic mass C-14) = ? g N-14. Post your work if you get stuck.
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