square both sides, then
(√(x-5))^2 = (2√6)^2
x-5 = 4(6)
x = 29
check:
Left Side = √(29-5
= √24
=√4 * √6
= 2√6 = Right Side
I don't understand how to get the answer to this "Radical equations" deal.
The problem I'm having trouble with is
(Square Root) x-5 = 2 (square root) 6
3 answers
3index 4x-15+3=square6x
3(6x+7)= 3(x-5)